Math, asked by mishthi7464, 2 months ago

Solve these for me please! ​

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Answered by hakimansarimd87
0

Answer:

yes I will solve this question

Answered by OoINTROVERToO
1
  • -4p × 7p = 28p²

  • 4x³ * -3x = -12x⁴

  • 5x * 0 = 0

  • -5x² * 7x³y²/10 = -7x⁵y²/2

  •  \sf \frac{ - 2 {p}^{2} q}{3}  \times  \frac{3p {q}^{2} }{4}  \times 5pqr =  \frac{5 {p}^{4}  {q}^{4}r }{2}

  • -7ab * -3a³ * -2ab²/7 = -6ab³

  •  \sf \:  \frac{ - 1 {x}^{2} }{2}  \times  \frac{ - 3xy}{5}  \times  \frac{2yz}{3}  \times  \frac{5xyz}{7}  =  \frac{ {x}^{3}  {y}^{2}z }{5}  \times  \frac{5xyz}{7}  =  \frac{ {x}^{4} {y}^{3} {z}^{2}   }{7}

  • -10pq³/3 × 6p³q/5 = -2pq³ × 2p³q = -4p⁴q
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