Math, asked by Suryavardhan1, 1 year ago

Solve these four questions

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Answered by rohitkumargupta
5
HELLO DEAR,

★ ( 1 ) ★

x = 1/(2 - √3)

x = (2 + √3)/(4 - 3(

x = (2 + √3)

now,

x² - 4x + 1

(2 + √3)² - 4(2 + √3) + 1

4 + 3 + 4√3 - 8 - 4√3 + 1

7 - 7 = 0

★ ( 2 ) ★

[ (3ⁿ + 3^(ⁿ - 1) ] / [ 3^(ⁿ + 1) - 3ⁿ ]

= [ (3ⁿ + 3ⁿ * 1/3 ] / [ 3ⁿ * 3 - 3ⁿ ]

= 3ⁿ [ 1 + 1/3 ] / 3ⁿ [ 3 - 1 ]

= (3 + 1)/3 / 2

= 4/3/2

= 2/3

★ ( 3 ) ★

plz open the link for your answer
https://brainly.in/question/3576525

★ ( 4 ) ★

x^a = y------( 1 )

y^ b = z------( 2 )

z^c = x--------( 3 )

from----( 1 ) , ----( 2 ) & -----( 3 )

x^a * y^b * z^c = xyz

on comparing both side,

we get,

a = 1 , b = 1 , c = 1

hence, abc = (1)(1)(1) = 1

I HOPE ITS HELP YOU DEAR,
THANKS
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