Solve these I will mark to him/her the brainiest if they answer the first
Answers
(i) (x-3)(x-7)
(ii) 100x^3 - 25xy^2
= x(100x^2 - 25y^2)
= x[(10x)^2 - (5y)^2]
= x(10x + 5y)(10x - 5y)
2)ax - ay + bx - by
= a(x - y)+ b(x-y)
= (x-y)(a+b)
3)1+p+pq+p^2q
= 1(1+p) + pq(1+p)
= (1+p)(1+pq)
4) 9y^2 - 30y + 25
= (3y)^2 - 2(3y)(5) + 5^2
= (3y - 5)^2
5) 3x^5 - 48x
= 3x(x^4 - 16)
= 3x [(x^2)^2 - 4^2]
= 3x(x^2 + 4)(x^2 - 4)
= 3x(x^2 + 4)(x^2 - 2^2)
= 3x(x^2 + 4)(x+2)(x-2)
6) (303)^2 - (297)^2
= (303 + 297)(303 - 297)
= 600 × 6
= 3600
Answer:
Step-by-step explanation:
(i) (x-3)(x-7)
(ii) 100x^3 - 25xy^2
= x(100x^2 - 25y^2)
= x[(10x)^2 - (5y)^2]
= x(10x + 5y)(10x - 5y)
2)ax - ay + bx - by
= a(x - y)+ b(x-y)
= (x-y)(a+b)
3)1+p+pq+p^2q
= 1(1+p) + pq(1+p)
= (1+p)(1+pq)
4) 9y^2 - 30y + 25
= (3y)^2 - 2(3y)(5) + 5^2
= (3y - 5)^2
5) 3x^5 - 48x
= 3x(x^4 - 16)
= 3x [(x^2)^2 - 4^2]
= 3x(x^2 + 4)(x^2 - 4)
= 3x(x^2 + 4)(x^2 - 2^2)
= 3x(x^2 + 4)(x+2)(x-2)
6) (303)^2 - (297)^2
= (303 + 297)(303 - 297)
= 600 × 6
= 3600
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