Question

Solve these i will mark you as brainliesr

Answer 1

Answer:

Step-by-step explanation:

Let AB be the flag nd BC be the building and P be the point on ground

In BCP, <BPC = 30

tan30 = BC/PC

1/root(3) = 10/Pc

PC = 10root(3)

In ACP, <APC = 45

tan 45 = AC/PC

1 = AB+BC/PC

PC = AB + BC

10root(3) = AB + 10

AB = 10root(3) - 10

AB = 10[ 1.732 - 1]

     = 10(0.732)

AB = 7.32m

so, length of flag staff = 7.32m and distance between building and point = 17.32m[10root(3)]

Hope for brainliest!!!