solve these if 1+2+3=8,2+3+4=18,3+4+5=32,4+5+6=50,6+7+8?
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Given:
1+2+3 = 8, 2+3+4=18, 3+4+5=32, 4+5+6=50.
To Find:
The value of 6 + 7 + 8 according to the above series is?
Solution:
The given problem can be solved by developing a common logic between every term.
1. According to the given data,
- The value of 1 + 2 + 3 is 8.
- The value of 2 + 3 + 4 is 18.
- The value of 3 + 4 + 5 is 32.
- The value of 4 + 5 + 6 is 50.
2. Conisder the solutions of the above additions,
=> 8, 18, 32, 50.
=> The second term is obtained as 18 = 8 + 10,
=> The third term is obtained as 32 = 18 + 10 + 4,
=> The fourth term is obtained as 50 = 32 + 10 + 4 + 4.
3. A common pattern can be observed from the above calculations. The next term can also be written in the similar pattern,
=> 5 + 6 + 7 = 50 + 10 + 4 + 4 + 4,
=> 5 + 6 + 7 = 72.
=> 6 + 7 + 8 = 72 + 10 + 4 + 4 + 4 + 4,
=> 6 + 7 + 8 = 98.
Therefore, the value of 6 + 7 + 8 according to the pattern is 98.
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