Question

Solve these linear equations :-
1) 10x + 21 = 111
2) 8x - 48 = 80 ​

Answer 1

$\tt{10x + 21 = 111}$

$\tt{10x = 111 - 21}$

$\tt{10x = 90}$

$\tt{x =\huge{ \frac{90}{10}}}$

$\tt{\therefore\: \huge{\boxed{\boxed x = 9}}}$

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$\tt{8x - 48 = 80}$

$\tt{8x = 80 +48}$

$\tt{8x = 128}$

$\tt{x =\huge{ \frac{128}{8}}}$

$\tt{\therefore\: \huge{\boxed{\boxed x = 16}}}$

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Answer 2

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⚘ Solution 1 ↓

➨ 10x + 21 = 111

➨ 10x = 111 - 21

➨ 10x = 90

➨ x = $\dfrac{90}{10}$

⟼ x = 9

Therefore, value of x = 9

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★ Verification ↓

➻ 10x + 21 = 111

➻ 10(9) + 21 = 111

➻ 90 + 21 = 111

➻ 111 = 111

⟼ LHS = RHS

Hence, verified.

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⚘ Solution 2 ↓

➨ 8x - 48 = 80

➨ 8x = 80 + 48

➨ 8x = 128

➨ x = $\dfrac{128}{8}$

⟼ x = 16

Therefore, value of x = 4

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★ Verification ↓

➻ 8x - 48 = 80

➻ 8(16) - 48 = 80

➻ 128 - 48 = 80

➻ 80 = 80

⟼ LHS = RHS

Hence, verified.

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