Question

Solve these pairs of linear simultaneous equation using the substitution method 3x-2y=10
4x+y=17

Answer 1

$\frac{x}{2} - \frac{x}{3} - 1 = 42x−3x−1=4\frac{3x - 2x}{6} = 4 - 163x−2x=4−1\frac{x}{6} = 36x=3x = 3 \times 6x=3×6x = 18x=18$