Solve these problems
Attachments:

Answers
Answered by
12
Answer:
f′(x)f′(x) gives you the slope of ff in x
Quite easily, if f′(x)f′(x) is positive, f(x)f(x) increases. If f′(x)f′(x) is negative, f(x)f(x) decreases.
We know that, for y∈R∗+y∈R∗+
0<y<1⇔ln(y)<00<y<1⇔ln(y)<0
ln(1)=0ln(1)=0
1<y⇔ln(y)>01<y⇔ln(y)>0
So we can write that
f′(x)>0⇔ln(x2x+1)>0⇔x2x+1>1f′(x)>0⇔ln(x2x+1)>0⇔x2x+1>1
f′(x)<0⇔ln(x2x+1)<0⇔x2x+1<1f′(x)<0⇔ln(x2x+1)<0⇔x2x+1<1
If x<−1
Answered by
0
answer in attachment^^
Attachments:


Similar questions