Question

solve these problems please​

Answer 1

Answer:

let 1st no.=x

2nd no.=x+1

3rd no.=x+2

according to question=x+x+1+x+2=33

3x+3=33

3x=33-3

3x=30

x=30/3

x=10

numbers are=10,11,12

plz mark as brainliest

Answer 2

Answer:

20, 22, 24

Step-by-step explanation:

let the first consecutive even no. be = x

so, the second consecutive even no. = x+2

and, the third consecutive even no. = x+4

So, the equation should be as follows:

x + x+2 + x+4 = 66

3x+6 = 66

3x = 66-6

3x = 60

x = 60/3

x = 20

x = 20

x+2 = 20+2 = 22

x+4 = 20+4 = 24