Question

solve these problems please​

Answer 1

Answer: okay yaru.it ees.

Answer 2

Let the original two digit number be : PQ

Given : Sum of the digits of this 2-digit number is 9

$:\implies$  P + Q = 9  ---------------- [1]

Given : The number obtained by reversing the digits is 27 more than the original number.

First let's reverse the original number

Reversed Number is : QP

As mentioned above, This reversed number QP is 27 more than the Original number PQ

If we think about this situation now, We come to a conclusion that the difference between the reversed number and original number is 27

$:\implies$  QP - PQ = 27  ---------------- [2]

Now consider a number, let's say 28

We can write the number 28 as : 2(10) + 8

Similarly, We can write the number QP as 10Q + P

We can write the number PQ as 10P + Q

Substituting the above values in Equation [2], We get :

$:\implies$  [10Q + P] - [10P + Q] = 27

$:\implies$  10Q + P - 10P - Q = 27

$:\implies$  9Q - 9P = 27

$:\implies$  9(Q - P) = 27

$:\implies$  Q - P = 3  ------------------ [3]

Now, Adding Equations [1] and [3] - We get :

$:\implies$  [P + Q] + [Q - P] = 9 + 3

$:\implies$  P - P + Q + Q = 12

$:\implies$  2Q = 12

$:\implies$  Q = 6

Substituting the value of Q in Equation [1], We get :

$:\implies$  P + 6 = 9

$:\implies$  P = 3

So, The Original two digit number is 36