Question

SOlVE THESE QUESTION​

Answer 1

Ans. 5.

Given,

Radius=21cm

We know,

Volume of a Sphere =4πr^3

=4×22/7×(21)^3

=38808cm^3

Answer 2

Explanation:

1. Angle A and angle D are the adjacent angle.

we know that,

Adjacent angles of a parallelogram are supplementary.

Hence ,

( 4x + 13 ° ) + ( 5x - 22° ) = 180

( 4x + 5x ) ( 22 - 13 ) ° = 180

9x - 9 = 180

9x = 180 + 9

9x = 189

x = 189 / 9

x = 21

Therefore, the angle will be ,

A = ( 4x + 13 )

4 × 21 + 13

= 84 + 13

= 97°

Angle D = ( 5x - 22 )

5 × 21 - 22

= 105 - 22 = 83 °

We know that ,

the opposite side and opposite angle of a parallelogram are congruent.

Therefore ,

Angle C = 97°

Angle B = 83 °

2. Given : In a circle centre c , QT is a diameter, CT = 13 and CP = 5

To find : length of chord RS

Construction: join points R and C.

CR ² = CP² + RP² [ PYTHAGORAS THEOREM]

(13)² = (5)² + RP² [ FROM 1 ]

[ 169 ] = 25 + RP²

169 - 25 = RP²

144 = RP²

RP = √144

RP = 12

(ii) Now seg CP _ L Chord RS ( given )

RP = (½) RS [ PERPENDICULAR DRAWN FROM THE CENTRE OF THE CIRCLE TO THE CHORD BISECTS THE CHORD]

12 = (½) RS ( FROM II)

RS = 2 × 12 = 24

The length of chord RS is 24 .

3. Quadrant

2. Quadrant

3. Quadrant

4. Y - axis

4. Sin theta = ⅘

Sin² thetha + cos²thetha = 1

(⅘)² + cos²thetha = 1

16/ 25 + cos² thetha = 1

cos² thetha = 1 - 16/25

cos² thetha = 25 - 16 / 25 = 9/25

cos thetha = √9/25

= √3/5 ²

cos thetha = 3/5

5. VOLUME OF SPHERE = 4/3 π R³

= 4/3 × π × 21 × 21 × 21

= 4 × π × 7 × 21 × 21

= 12,348 π

$hope \: it \: helps \: you \:$