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Step-by-step explanation:
f (x)=x2-2x+3
zeroes=p and q
p+q= -b/a=2
pq= c/a=3
New zeroes =p+2,q+2
sum of zeroes=p+2+q+2
=p+q+4
=2+4
=6=-b/a
product of zeroes = (p+2)(q+2)
=pq+2p+2q+4
=3+2×(p+q)+4
=3+2×3+4
=3+6+4
=13
=c/a
Answered by
1
Answer:
roots of a given quadratic equation is 1+i√2,1-i√2
Step-by-step explanation:
as we know,if they give the roots then we can use this x^2-(p+q)X+pq
where p and q are the roots of the required equation by substituting we can the required equations
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