Math, asked by tayalkeshav, 1 month ago

Solve these question...
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Answers

Answered by atikkhan0095
1

Step-by-step explanation:

f (x)=x2-2x+3

zeroes=p and q

p+q= -b/a=2

pq= c/a=3

New zeroes =p+2,q+2

sum of zeroes=p+2+q+2

=p+q+4

=2+4

=6=-b/a

product of zeroes = (p+2)(q+2)

=pq+2p+2q+4

=3+2×(p+q)+4

=3+2×3+4

=3+6+4

=13

=c/a

Answered by huralishannu32
1

Answer:

roots of a given quadratic equation is 1+i√2,1-i√2

Step-by-step explanation:

as we know,if they give the roots then we can use this x^2-(p+q)X+pq

where p and q are the roots of the required equation by substituting we can the required equations

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