Question

solve these questions

Answer 1

CHECK POINT 6.1

1) ( i ) Given

length = 36 cm

and

breadth = 20 cm

Perimeter of rectangle = 2 ( l + b )

=> 2 ( 36 + 20 )

=> 2 × 56

=> 112 cm

Area of rectangle = l × b = 36 × 20= 720 cm

Do all remaining questions as same as above is solved


Hope it will helps you

Answer 2

Hii Mate !!


Here is your answer :


Solution :


(1) Length of rectangle ( L ) = 36 cm

And ,Breadth of rectangle ( B ) = 20 cm.


Therefore,


Perimeter of rectangle = 2 ( Length + Breadth ) = 2 ( 36 + 20 )

=> 2 * 56

=> 112 cm


And,


Area of rectangle = Length × Breadth

=> 36 × 20 = 720 cm²


(2) Length of rectangle ( L ) = 3.2 m


Breadth of rectangle ( B ) = 1.8 m


Therefore,

Perimeter of rectangle = 2 ( Length + Breadth ) = 2 ( 3.2 + 1.8 ) = 2 * 5 = 10 cm


And,

Area of rectangle = Length × Breadth = 3.2 × 1.8 = 5.76 cm².


(3) Length of rectangle ( L ) = 1 m 50 cm = 150 cm.


Breadth of rectangle ( B ) = 70 cm.


Therefore,

Perimeter of rectangle = 2 ( Length + Breadth ) = 2 ( 150 + 70 ) = 2 ( 220 ) = 440 cm.


And,

Area of rectangle = Length × Breadth = 150 × 70 = 10500.




(4) Side of square ( S ) = 25 cm.


Therefore,

Perimeter of square = 4 × Side = 4 × 25 = 100 cm.

And,

Area of square = ( Side)² = 25² = 625 cm².

(5) Side of square ( S ) = 1.2 m


Therefore,

Perimeter of square = 4 × 1.2 = 4.8 cm.

And,

Area of square = (side)² = 1.2² = 1.44 cm²


(6) Side of square ( S ) = 0.78


Therefore,

Perimeter of square = 4 × 0.78 = 3.12 cm

And,

Area of square = Side² = 0.78² = 0.6084 cm².


Hope it helps you ♥


By Rishi403.

BeBrainly..