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Let's assume two numbers x and y, such that :- x > y
ATQ :-
=> x = y + 12
and, x + y = 10
=> (y + 12) + y = 10
=> 2y + 12 = 10
=> y + 6 = 5
=> y = -1
So, x = y + 12 = -1 + 12 = 11
Thus, x = 11 and y = -1
Hope this helps.....
ATQ :-
=> x = y + 12
and, x + y = 10
=> (y + 12) + y = 10
=> 2y + 12 = 10
=> y + 6 = 5
=> y = -1
So, x = y + 12 = -1 + 12 = 11
Thus, x = 11 and y = -1
Hope this helps.....
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