Math, asked by d3graph, 4 months ago

solve these Questions and give the answer with explanation of all​

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Answered by shreekrishna35pdv8u8
1

ans

  1. a
  2. b
  3. c

rustisi5sztizykzkt


d3graph: thx and sorry also
d3graph: because u did not give the explanation
d3graph: Sorry is for this
d3graph: thx for ur answer
shreekrishna35pdv8u8: that's k I thought it's 1 mark ans so...
d3graph: it's ok
Answered by Saaad
1

\huge{Question :}

Mark (√✔) against the correct answer in each of the following:

1. The simple interest on 6250 at 4% per annum for 6 months is

(a) 125

(b) 150

(c) 175

(d) 135

2. A sum amounts to 3605 in 219 days at 5% per annum. The sum is

(a) 3250

(b) 3500

(c) 3400

(d) 3550

3. At simple interest a sum becomes 6/5 of itself in 2 1/2 years. The rate of interest per annum is

(a) 6%

(b) 7 1/2%

(c) 8%

(d) 9%

\huge\bf{Answer :}

\huge\sf\implies{1.(a) 125}

Principal = Rs6250, SI = 4%p.a., Time = 6months = (6/12) = (1/2) years

SI = (P×R×T)/100

=(6250×4×(1/2))/(100)

=6250×4×(1/2)×(1/100)

=(6250×4×1×1)/(2×100)

=(6250×2)/(100)

=(6250/50)

=Rs.125

\huge\sf\implies{2.(b) 3500}

Let the required sum be ₹ x

Let the required sum be ₹ x Then, SI = (P × R × T)/ 100

Amount = P + SI

= x + [(x × R × T)/ 100]

= x [1 + ((R × T)/ 100)] x

= Amount/ [1 + ((R × T)/ 100)]

= 3605/ [1 + ((5/100) × (219/365))]

= (3605 × 36500)/ 37595 x = ₹ 3500

\huge\sf\implies{3.(c) 8}

Let the required sum be ₹ x

Rate of interest = r %

Time = 2½ years = 5/2 years

Amount = (6/5) × sum

Amount = principal + SI

(6/5) × x = x + [(P × R × T)/100]

= (6/5) x = x + [(x × r × 5)/ (100 × 2)]

= (6/5) = (1 + (r/40))

= r = (40 × (1/5))

= r = 8%

\huge\sf\implies{Thanks : ❤}

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