Solve these questions please..
1)The time taken for 30 oscillations of a simple pendulum as measured by a stopwatch is 51 seconds. What is the time period of the simple pendulum?
2)Calculate the time period of a simple pendulum if it takes 48 seconds to complete 12 oscillations.
3)A simple pendulum has a time period of 1.4 seconds. Calculate the time taken by the pendulum to make 40 oscillations.
4) Time period of a simple pendulum is 2 seconds. What is its frequency?
5) A simple pendulum completes 40 oscillations in a minute.
Find its frequency and time period.
Answers
Answer:
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Explanation:
1)Number of oscillations n=20
Time taken =25 s
∴ Time period of oscillation T=
20
25
=1.25 s
Given :
Error in time for 20 oscillations, ΔT=0.2 s
Hence error in time for 1 oscilations, ΔT
′
=
n
0.2
= s
∴ Percentage error =
T
ΔT
×100=
20×1.25
0.2
×100=0.8 %
2)1 oscillation = Time (t) / no.of.oscillations = 48/12
then
1 Oscillation = 4 Seconds
3)Time taken to complete on oscillation =1.4
Time taken to complete 40 oscillation = 1.4 *40
= 56.0
So ,total time taken to complete 40 oscillation= 56 seconds
4)The Time period of a simple pendulum is given as 2 seconds.
The frequency is given as the inverse of time period, that is, f=
T
1
f=
2
1
=0.5Hz
5)Given
Number of Oscillations, N=40
Time t=1min
Frequency f=
t
N
=
60
40
=0.667Hz
Time period,T=
f
1
=1.5sec
Hence, frequency is 0.667Hz and time period is 1.5sec
Answer:
1) Time period = T/no.oscillation
time =51 sec
oscillation=30 oscillation so,
time period =51/30
=17/10( after simplifying it) =1.7 sec