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Answers
Answer-
The total power two tube lights consume = 40+40
= 80W
Power × hours = Wh
80 × 5 = 400Wh
To convert into kWh, multiply and divide by 1000
= 400Wh × 1000/1000
= 400kWh /1000 (As 1000 = k)
= 0.4kWh
This is the kWh the tube lights consumed per day.
For one month, multiply kWh of one day with 30.
Hence,
kWh of one month = 0.4 × 30
= 12kWh
Therefore, tube lights consume total 12kWh in one month.
Similarly, for the TV and fan.
Watt-hours = 60 ×8
= 480Wh
To convert into kWh, multiply and divide by 1000
kWh = 480Wh × 1000/1000
= 480kWh/1000 (As 1000 = k)
=0.48kWh
This is the kWh the TV consumed per day.
For one month, multiply kWh of one day with 30.
Hence,
= 0.48 × 30
=14.4kWh
Similarly for fan,
Watt-hours = 80 × 12
=960Wh
To convert into kWh, multiply and divide by 1000
kWh = 960Wh × 1000/1000
= 960kWh/1000 (As 1000 = k)
=0.96kWh
This is the kWh the fan consumed per day.
For one month, multiply kWh of one day with 30.
Hence,
= 0.96 ×30
=28.8kWh
Total kWh consumed by all of them in one month = 28.8+ 12 + 14.4
= 55.5kWh
Electric energy is 3.10 per kWh.
The cost of electricity = 3.10 × 55.5
=172.07
Answer:
Power consumption of 2 tube light= 2*40 W
Daily power consumption of tube light P1=2*40*5
=400W
Power consumption of fan=80W
Daily Power consumption of fan P2 =80*12
=960 W
Power consumption of TV=60W
Daily power consumption of TV P3=60*8
=480 W
Total power consumption=P1+P2+P3
=400+960+480
=1840 W
=1840/1000 KWh
=1.84 KWh
Total monthly consumption of electricity=1.84*30
=55.2 KWh
Cost of electricity= ₹3.10 /KWh
Total monthly cost of electricity=₹3.1*55.2
=₹171.12