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=5p2-25p+20=5(p2-5p+4)
=5[p2-4p-p+4]
=5[p(p-1) -4(p-1) ]
=5[(p-1) (p-4) ]
hence, (5p^2-25p+ 20÷(p-1) =
5(p-1) (pyr)
(p-1)
=5(p-4)
hence, (5p^2 -25p+20) ÷(p-1) =5 (p-4) .
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