Math, asked by SANJAILION, 11 months ago

solve these questions
1) \: {2}^{x}  +  {4}^{x}  = ( {8})^{ \frac{1}{3} }  \times (32)^{ \frac{1}{5} }  \\  2) \: ( \frac{2}{3} )^{ \frac{4}{3} }  \div ( \frac{2}{3} ) ^{ \frac{5}{3} }

Answers

Answered by Anonymous
25

Answer:-

(i) \: 2 {}^{x}  + 4 {}^{x}  = 8 {}^{ \frac{1}{3} }  \times 3 {}^{2 \frac{1}{5} }  \\  = 2 {}^{x}  + (2 {}^{2} ) = 2 {}^{3 \times  \frac{1}{3} }  \times (2 {}^{5} ) \frac{1}{59}  \\  = 2 {}^{x}  + 2 {}^{2x}  = 2 {}^{3 \times  \frac{1}{3} } \times 2 {}^{5 \times  \frac{1}{5} }   \\  = 2 {}^{ x }  + 2 {}^{2x}  = 2 \times 2 \\  = 2 {}^{ x}  + 2 {}^{2x}  = 2 {}^{2}  \\  = x + 2 {}^{x}  = 2 \\  3  {}^{x} = 2 \\ x =  \frac{2}{3}

(ii) \: ( \frac{2}{3}    ) {}^{ \frac{4}{3} }  \div ( \frac{2}{3} ) {}^{ \frac{5}{3} }  \\  = ( \frac{2}{3} ) {}^{ \frac{4}{3 } -  \frac{5}{3}  }  \\  = ( \frac{2}{3} ) {}^{ \frac{ - 1}{3} }  \\  =( \frac{3}{2} ) {}^{ \frac{1}{3} }  = ( \frac{27}{8} )

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