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Answer 1

Q43) In the upper part of circuit, 2 and 2 μF are in series.

Equivalent capacitance = 2/2 = 1 μF

This 1μF is parallel to 1μF.

Equivalent Capacitance = 2 μF

Total charge = Q = CV

Q = 2 (2) = 4 μC

Capacitance of upper capacitors (1μF) is equal to capacitance of lower capacitor(1μF).

Hence charge is divided equally between upper and lower capacitors.

So charge in lower capacior = 2 μC

Charge in any of the upper capacitor = 2 μC

So answer is (4)