Math, asked by koraniriya, 1 year ago

Solve these sums - Expansion

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Answers

Answered by PATELKUNJ

(i)
$4x {}^{2} - 1$

koraniriya: With all steps

Answered by Rahi39

1) 4x²+2x-2x-1=0
2) -4x²-2xy+2xy+y²=0
3)16a²+28ab-28ab-49b²=0
4) (a²-b²)(a²+b²)=a4+a²b²-a²b²-b4=0

Hope this helped you. :)

Rahi39: basically (4x-1)(4x+1)=[4x]{4x+1}, (-1){4x+1}

Rahi39: so you get 16x²+4x-4x-1=0....

Rahi39: just for an example, I told this

koraniriya: Can u send the working please

Rahi39: ok

koraniriya: Thank you

koraniriya: Right now....It's urgent

koraniriya: Yr answers are wrong

Rahi39: Hey, just cut the plus and negative values... then your answers will be correct

Rahi39: I didn't cut becoz you need to understand

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