Question

Solve these two problems please

Answer 1

use the formula of infinite many solution a1/a2 = b1/b2 = c1/c2 
let a1=2 , a2 =3 and a3 = -7
b1=(m-1) , b2= (m+1) and b3 = -(3m-1)

Answer 2

Q. No 10


LHS=SinA/1-cosA
=sinA(1+cosA)/1-cos²
= sinA+sinA.cosA/sin²A
= sinA/sin²A + sinA.cosA/sin²A
=1/sinA + cosA/sinA
= cosecA + cotA