solve these two questions please
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1. we know the divisiblity test of 3 I.e. the sum of the digits in a number is divisible by 3 then the number is divisible by 3
so
7x3
sum of digits
= 7 + x + 3
= 10 + x
so nearest dividend of 3 from 10 is 12
so x = 2
Then 15
x = 5
Then 18
x = 8
Then 21
so x = 11
it is NO valid because it contains 2 digits
so the numbers are
723 , 753 , 783
so
7x3
sum of digits
= 7 + x + 3
= 10 + x
so nearest dividend of 3 from 10 is 12
so x = 2
Then 15
x = 5
Then 18
x = 8
Then 21
so x = 11
it is NO valid because it contains 2 digits
so the numbers are
723 , 753 , 783
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