Physics, asked by RoyalChora38, 10 months ago

Solve these two questions plz::

1) Mass of moon is 7.31 × 10²² kg and its radius is 1.7 × 10^6 m. Determine acceleration due to gravity on its surface. [G= 6.7 × 10^-11 Nm² kg^-2]

2) Find the weight of an object at a height 6400 km above the Earth's surface. The weight of the object at the surface of the earth is 20 N and the radius of the earth is 6,400 km.

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Answers

Answered by Anonymous
19

\huge\mathfrak\purple{Konichiwa!}

\huge\bold{Answers:-}

1) We know that,

g= GM/d²

=> g = 6.7 × 10^-11 × 7.31 × 10²²/ (1.7 × 10^6)²

g= 1.69 m/ [The required solution!]

______________________________________

2) We have,

★ W = mg = 20 N.

★ Mass = 20/9.8 = 2.04 kg.

★ g = GMe/Re²

Now,

W= mg [Re²/Re² + H²]

 = 20 \:  \alpha  \: ( \frac{6400}{12800} )

 = 20 \times  \frac{1}{4}

= 5 N. [ The required solution! ]

______________________________________

Hope it helps...❣❣❣

⭐❤✨♥⭐❤✨♥⭐

Be Brainly...✌✌✌

WALKER

Answered by Ravispssbp
2

Hey my lovely mate ♥️♥️

your answer:::...

Answers:−

⛄ 1) We know that,

g= GM/d²

=> g = 6.7 × 10^-11 × 7.31 × 10²²/ (1.7 × 10^6)²

☞ g= 1.69 m/s² [The required solution!]

______________________________________

⛄ 2) We have,

★ W = mg = 20 N.

★ Mass = 20/9.8 = 2.04 kg.

★ g = GMe/Re²

Now,

W= mg [Re²/Re² + H²]

= 20 \: \alpha \: ( \frac{6400}{12800} )=20α(

12800

6400

)

= 20 \times \frac{1}{4}=20×

4

1

= 5 N. [ The required solution! ]

______________________________________

✔✔✔✔✔✔✔✔

Hope it helps...❣❣❣

⭐❤✨♥⭐❤✨♥⭐

Be Brainly...✌✌✌

Thankyou....

Regards :Dr Ravi....♥️♥️♥️♥️

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