Solve these two questions, quickly.......
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3
1.
Angle AEC = Angle ACE ( Isosceles Triangle)
Let angle AEC be X
X+X+40=180
2x=140
X=70
Angle BEC= 180- 70
= 110
Angle ECB= 180-70-75
=35
Angle EBC= 180-110-35
= 35
ANGLE EBC =ECB
Thus it forms an Isosceles Triangle so EB=EC
Angle AEC = Angle ACE ( Isosceles Triangle)
Let angle AEC be X
X+X+40=180
2x=140
X=70
Angle BEC= 180- 70
= 110
Angle ECB= 180-70-75
=35
Angle EBC= 180-110-35
= 35
ANGLE EBC =ECB
Thus it forms an Isosceles Triangle so EB=EC
anchukumarraipb9puq:
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Answered by
2
(2) given,
angle A=70°
you know that,
angle BOC=1/2×angleA
angle BOC=90°-1/2×angleA
=90°-1/2×70
=90°-35
=55
hope this help you
angle A=70°
you know that,
angle BOC=1/2×angleA
angle BOC=90°-1/2×angleA
=90°-1/2×70
=90°-35
=55
hope this help you
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