Question

solve thier pair of linear equations x+3y=6 , 2x-3=12




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Answer 1

Answer:

IN FIRST EQUATION ,

Subtract x x from both sides of the equation. Divide each term by 3 3 and simplify. Divide each term in 3y=6−x 3 y = 6 - x by 3 3 . The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept.

AND IN SECOND,

2x+3y=12is the standard form for a linear equation. To determine the slope, solve the equation for y in order to convert to the slope-intercept form

y=mx+b, where m is the slope and b

is the y-intercept.

2x+3y=12 Subtract2x from both sides.

3y=−2x+12

Divide both sides by 3.

y=−2/3x+12/3

y=−2/3x+4

The slope is−2/3

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