Question

Solve third question please and fast

Answer 1

Answer:

Given that AB=BC=CD

We know that in a circle equal chords subtend equal angles at the centre .

Which implies that <AOB=<BOC=<COD

<AOB=<BOC=<CID=40 degrees

i) So <AOC= <AOB+ <BOC= 40+40=80 degrees

ii) <BOC= 40 degrees( Proved above )

iii) <AOD=40+40+40= 120 Degrees.

Hope it helps. All the best .