Math, asked by shanudhiman009, 11 months ago

Solve this
1/π[4π²/2-4π³/3]

Answers

Answered by ayushghogre7
0

p stands for pie here

1/p[4p2/2-4p3/3]

1\p[4p2 x 3 /2-4p3]

1/p x p2 [4x3/2-4p]

p [12/(2-22/7)]                                                       (putting the value of p=22/7)

p [12/(14-22/7)]    

p[12/(-8/7)]      

p[12x7/8]

p[21/2]

22/7[21/2]

11x3

33








hope it helps


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