Question

Solve this:-
1/x+y=1/x+1/y
Find --》 x^3-y^3=?

Answer 1

Answer:

1/x+y=x+1/y

1/x-1/y=x-y

y-x/xy =x-y

-(x-y) /xy=x-y

-1=xy

xy=-1

x=-1/y---------------(1)

x³-y³=(x-y) (x²+xy+y²)

=(x+1/x) (1/x²-1+1/x²) ----------------(using 1)

=(x²+1)/x(2-x²)/x²