solve this 10+1 maths complex number
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[(√5+i/2)](√5-2i)]÷(6+5i)
√=a×a=a2
√5=5×5=25
i/2=2i
(√5-2i)
5×5=25+2i=27i
6+5i=11i
23i+27i=50√i
50÷11=4√i÷2=
2√i
√=a×a=a2
√5=5×5=25
i/2=2i
(√5-2i)
5×5=25+2i=27i
6+5i=11i
23i+27i=50√i
50÷11=4√i÷2=
2√i
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