Question

solve this...........................​

Answer 1

★ Refer to attachment...

hope it helps....

Answer 2

Answer:

second level

Explanation:

Radius of nth orbit is given by,  n²h²/4π²mKZe²

i.e, r ∝ n²/Z

For hydrogen,  Z = 1, n = 1 in ground state.

∴ n²/Z = 1²/1 = 1

For Berylium, Z = 4, as orbital radius is same, n²/Z = 1

∴ n² = 1 x Z = 1 x 4 = 4

∴ n = √4 = 2

Hence n = 2.

Thus, second level of triply ionised Be⁺⁺⁺  has same radius as the ground state of hydrogen.