Question

solve......
..........this! ​

Answer 1

Refer the attachment....✌

Answer 2

Answer:

${\bold{\green{\huge{Your\:Solution}}}}$

$\huge{\bold{\boxed{\boxed{\mathbb{\red{EXPLANATION}}}}}}$

IN ΔABC  , PQ║AB

Applying Thales' theorem, we get:

$\frac{CA}{PB}=\frac{CQ}{QA}.....(1)$

$Similarly.$

$applying,Thales'\:theorem\:in$   ΔBDC

$Where$  PR║DM  we get:

$\frac{CA}{PB} =\frac{CA}{RD}.....(2)$

$Hence\:from\:(1)\:and\:(2),\:we\:have$

$\frac{CQ}{QA}=\frac{CR}{RD}$

$Applying\:the\:converse\:of\:Thales’\:theorem,\:we\:conclude\:that$  QR ‖ AD in ∆ ADC.

$This\:completes\:the\:proof$