Question

solve this.....................​

Answer 1

Answer:

here is your answer dear

Answer 2

Answer:

sinA+cosA =√2

squaring on both sides

(sinA+cosA)^2=(√2)^2

sin^2A+cos^A+2sinA*cosA=2

2sinA*cosa=2-1

sinA*cosA=1/2------_1】

now ) putting on ur question

tanA+cotA

=)sinA/cosA+cosA/sinA

=)sin^2A+cos^2A/sinA*cosA

=)1/1/2 from 1)

now, it's 2 Ans.