Question

Solve this!!!!!!!!!!!!!!!!!!!!!!

Answer 1

break all components of F2 and F in vertically and horizontally .

from Vertica equilibrium
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F2sin45° + Fsin∅ = F1
given,
F2 = 20√2 N
F1 = 60 N

so, 20√2 × 1/√2 + Fsin∅ = 60

Fsin∅ = 40 N ------(1)

from horizontal equilibrium
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F3 + F2cos45° = Fcos∅

10 + 20√2 × 1/√2 = Fcos∅

Fcos∅ = 30 N --------(2)

divide eqns (1) and (2)

tan∅ = 4/3

∅ = tan^-1( 4/3)

again ,

take square of both equations then add

F²sin²∅ + F²cos²∅ = 40²+30²

F²( sin²∅ + cos²∅) = 2500

F² = (50)²

F = 50 N

hence, F = 50N and ∅ = tan^-1( 4/3)