Solve this 12th & 13th q. Plz
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I Know only 13q
In ∆ ADC, By Pythagoras theorem
AC² = AD²+ CD²-------->(1)
In right ∆ADC, By Pythagoras theorem
AB²= AD² + BD²--------> (2)
Subtracting (1) from (2),
We get,
AB²-AC² = BD²-CD²
=> so, AB² + CD² = BD² +AC²
Hence proved...
Hope this helps you friend
Thanks ✌️ ✌️
In ∆ ADC, By Pythagoras theorem
AC² = AD²+ CD²-------->(1)
In right ∆ADC, By Pythagoras theorem
AB²= AD² + BD²--------> (2)
Subtracting (1) from (2),
We get,
AB²-AC² = BD²-CD²
=> so, AB² + CD² = BD² +AC²
Hence proved...
Hope this helps you friend
Thanks ✌️ ✌️
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