Question

Solve this 12th & 13th q. Plz

Answer 1

I Know only 13q

In ∆ ADC, By Pythagoras theorem

AC² = AD²+ CD²-------->(1)

In right ∆ADC, By Pythagoras theorem

AB²= AD² + BD²--------> (2)

Subtracting (1) from (2),
We get,

AB²-AC² = BD²-CD²

=> so, AB² + CD² = BD² +AC²

Hence proved...

Hope this helps you friend
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