Question

solve this 13 question

Answer 1

Let value of 1st prize be x

So, 2nd prize is $\frac{3}{4} x$ and 3rd prize be $\frac{1}{2}$×$\frac{3}{4}x$

According to question,

x + $\frac{3}{4} x$ + $(\frac{1}{2}$×$\frac{3}{4} x)$ = 2550

⇒ x + $\frac{3}{4} x$ + $\frac{3}{8} x$ = 2550

⇒ $\frac{8x+6x+3x}{8}$ = 2550

⇒ 8x + 6x + 3x = 20400

⇒ 17x = 20400

⇒ x = $\frac{20400}{17}$

⇒ x = 1200

∴ 1st prize = ₹1200

2nd prize = $\frac{3}{4}$×1200 = ₹900

3rd prize = $\frac{1}{2}$×900 = ₹450

Hope I got everything correct.