Math, asked by Anonymous, 8 months ago

Solve this.....!!!


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Answered by HariesRam
18

here \\  \\ T =  \sqrt{ \frac{2L}{g} }  +  \frac{L}{V }  \\  \\delta \:  T = deta \: A + delta \: B \\  \\ delta \: T =  \sqrt{ \frac{2}{g} }  \:  \times  \frac{delta \: L}{2 \sqrt{L} } \:   +  \frac{delta \: L}{V}  \\  \\ delta \: T =  \sqrt{ \frac{1}{2gL} }  \times delta L \: +   \frac{delta \: L}{V}  \\  \\ 0.01 =  \frac{1}{ \sqrt{2 \times 10 \times 20} }  \times delta \: L +  \frac{delta \: L}{30}  \\  \\ 0.01 = delta \: L \:   | \frac{1}{20}  +  \frac{1}{300} |  \\  \\ on \: calcutating \: we \: get \\  \\ deta \: l \:  = 0.185 \\  \\  \frac{delta \: L}{L}   \times 100 =  \frac{0.185}{20}  \times 100 = 1\%

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Answered by ItzShrestha41
9

Step-by-step explanation:

Answer \huge\orange{\ddot\smile}

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