Math, asked by tvishamishra, 7 months ago

Solve this (-2^3)*(-2)^7/3*4^6

Answers

Answered by amankumaraman11
0

 \frac{ {( - 2)}^{3}  \times  {( - 2)}^{7} }{ {4}^{6} }  \\  \\  \frac{ {( - 2)}^{3 + 7} }{ { \big[  {(2)}^{2} \big]}^{6} }   =  \frac{ {( - 2)}^{10} }{ {2}^{12} } \\  \\  -   \bigg[\frac{ {2}^{ \tiny{10}} }{ {2}^{ \tiny{12}} }  \bigg] =  \:  \:  - [ {2}^{ \tiny{10 - 12}} ] \\  \\  -  {(2)}^{ - 2}  =  \frac{ - 1}{ {2}^{ \tiny2} }  \\  \\ \boxed{    \frak\red {\huge{ \:  \:  \:  \frac{ - 1}{4} \:  \:  \:  }}}

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