Math, asked by rudra733, 11 months ago

solve this 2 any genius in brainly for 100 points ​

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Answers

Answered by rudra09
5

hope its help u my dear.........

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Answered by kameena1
0

ax² + bx + c =0

alpha + beta = -b/a

a.alpha + a.beta = -b

a.alpha + b = -a.beta ------(1)

in the same way ,

a.beta + b = -a.alpha -----(2)

alpha.beta = c/a

a.alpha.beta = c ----------(3)

={alpha /( a.beta + b)}³ -{ beta /( a.beta +b)}³

put equation (1)and (2) here

={ alpha/( -a.beta)}³ -{ beta/( -a.alpha)}³

=-alpha/a³.beta³ + beta /a³alpha³

=(-alpha⁴ + beta⁴)/(a.alpha.beta)³

=(beta² -alpha²)(beta²+alpha²)/(a.alpha.beta)³

=(beta -alpha)(alpah-beta)(b²/a² -2c/a)/(c)³

beta -alpha =±√(b²/a² -4c/a)

use this ,

=(±√(b²/a² -4c/a))(-b/a)(b²/a² -2c/a)/c³

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