solve this 2 question 21 and 23rd class 11 chapter limits and derivative
Answers
Answer:
(21) 1 / 2
(23) 2√a
Step-by-step explanation:
plzzz see the attachment
Now for question ( 21 )
(1) In second step we multiply numerator and denominator by conjugate of numerator.
(2) In third step applying identity,
a² - b² = ( a + b ) ( a - b )
(3) In fifth step we take out x as common from numerator and then x cancel out from numerator and denominator
(5) In sevnth step we put x = 0 in it and we get ans as 1 / 2 .
For question ( 23 )
(1) In second step we mutiply in numerator and denominator by conjugate of denominator
(2) In third step we apply identity,
a² - b² = ( a+ b ) ( a - b )
(3) In fifth step a and( -a ) cancel out each other
(4) In sixth step 2x cancel out from numerator and denominator
(5) In 8th step we put x= 0 in it and we get ans as
2√a