solve this ?????????.........
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Step-by-step explanation:
cot40/tan50-cis35/2sin55=
cot40/tan(90-40)-cos35/2sin(90-35)
=cot40/cot40-cos35/2cis35.
=1- 1/2=2-1/2=1/2
NOTE:SUN(90-@)=COS@
COS(90-@)=SIN@
AND COT AND TAN ,SEC AND COSEC ARE INTERCHANGED LIKE THAT
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