Question

solve this ..…..........​

Answer 1

Answer:

in triangle ABC,

AB=AC

therefore, angle ABC=angle ACB=x

[if opposite sides are equal then opposite angles are equal]

angle BAC=84°

angle BAC+angle ABC+angle ACB=180°

(ANGLE SUM PROPERTY)

84°+x°+x°=180°

2x°+84°=180°

2x°=180°-84°

2x°=96°

x=96°/2=48°

therefore, angle ABC=angle ACB=x=48°

angle ACB +angle ACD=180°(Linear pair)

48°+ angle ACD=180°

angle ACD=180°-48°

angle ACD=132°

in triangle ACD,

AC=CD

angle CAD=angle CDA=y

[if opposite sides are equal then opposite angles are equal]

angle ACD+angle CAD+angle CDA=180°

132°+y°+y°=180°

2y°+132°=180°

2y°=180°-132°

y=48°/2=24°

therefore, y=24°