Solve this
√28+√98+√147
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1
√28 + √98 + √147
√28 = √(7*4) = 2√7
√98 = √(49*2) = 7√2
√147 = √(49*3) = 7√3
Therefore,
√28 + √98 + √147 = 2√7 + 7√2 + 7√3
√28 = √(7*4) = 2√7
√98 = √(49*2) = 7√2
√147 = √(49*3) = 7√3
Therefore,
√28 + √98 + √147 = 2√7 + 7√2 + 7√3
Answered by
3
√28+√98+√147
=√2*2*7 + √7*7*2 + √7*7*3
=2√7 + 7√2 + 7√3
=√2*2*7 + √7*7*2 + √7*7*3
=2√7 + 7√2 + 7√3
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