Question

solve this 2nd and 3rd
no spam answers needed

Answer 1

hey there...
2) smallest prime no. is :2
smallest composite no. is :4
so,
2=2×1
4=2×2
and HCF (2,4)=2×1="2"

3) P(x,y)------------------------O(o,o)

then find distance..
d= root of (x1-x2)^2+(y1-y2)^
d= root of (x-0)^2+(y-0)^2
d= root of (x)^2+(y)^2

so answer for this question is [root of x^2+y^2]

Answer 2

2. The smallest prime number is 2
and composite no is 4

therefore HCF(2 , 4 ) = 2

3 . BY USING DISTANCE FORMULA
root of ( x2-x1)square + ( y2- y1) square

ur answer will come root of (xsquare+ ysquare)

i hope it helps u buddy ✌✌✌