solve this 2sinA - 3cosA = 3
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hey there,
2 sinA/ 3 cosA = 3/4
TanA = 3/4 x 3/2 = 9/8 = perpendicular/ base
So hypotenuse = v9 2 + 8 2 = v145
so cosA = 8/ v145, cosecA = v145/ 9
Hope this helps!
2 sinA/ 3 cosA = 3/4
TanA = 3/4 x 3/2 = 9/8 = perpendicular/ base
So hypotenuse = v9 2 + 8 2 = v145
so cosA = 8/ v145, cosecA = v145/ 9
Hope this helps!
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