Question

solve this
(2x+3)(x-2)=x(x+1)

Answer 1

(2x+3)(x-2)=x(x+1)
2x^2+3x-4x-6=x^2+x [open the brackets]

2x^2-x-6=x^2+x

Move the numbers on RHS to LHS

2X^2-x^2-x-x-6=0

X^2-2x-6=0

Now, we will use the quadratic formula
Which is: D=b^2-4ac Where D is the discriminent

And, a=1, b=-2, c=-6(coefficients)

Putting these values in the formula

D=(-2)^2-4x1x-6

D=4+24=28

Now according to the quadratic formula x=-b+- D^1/2 whole upon 2a

Now putting values in this we get two values of x

X= 2+2root7 whole upon 2

And the second value is:

X=2-2root7 whole upon 2

DONT THINK OF IT AS VERY TOUGH, ITS QUITE EASY AND YOU WILL GET THE HANG OF IT WITH TIME.

HOPE THIS HELPS.