solve this..2x+3y=sin x differentiate that.
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differentiate both sides wrt x
2+3(dy/dx)=cosx
dy/dx=cosx-2/3
2+3(dy/dx)=cosx
dy/dx=cosx-2/3
Barbie01:
plz clear that
#it
u mean delete?
no no
i'm not understanding this...if u clear it then i'm thankful 2 you
oh... look I have differentiated it W. r. t X both sides.. in Lhs...we have 2x+y which on differentiation becomes 2 and (dy/dx) respectively... in rhs we have sinx, whose differentiation is cosx
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