Question

solve this 3x+1/5=2-x

Answer 1

$\mathbb{ SOLUTION }$ :

$3x + \frac{1}{5} = 2 - x \\ \\ = > 3x + x = 2 + \frac{1}{5}$

By taking (-x) to LHS and $\frac{1}{5}$ to RHS

$= > 4x = \frac{10 - 1}{5}$

Taking 5 as LCM in RHS

$= > 4x = \frac{9}{5} \\ \\ = > x = \frac{9}{5} \div 4 \\ \\ = > x = \frac{9}{5} \times \frac{1}{4} \\ \\ \therefore x = \frac{9}{20}$


VERIFICATION

LHS
$3x + \frac{1}{5} \\ \\ = 3 \times \frac{9}{20} + \frac{1}{5} \\ \\ = \frac{31}{20}$
RHS
$2 - x \\ \\ = 2 - \frac{9}{20} \\ \\ = \frac{31}{20}$

$\therefore$ LHS = RHS (verified)

Answer 2

Answer:

3x+

5

1

=2−x

=>3x+x=2+

5

1

By taking (-x) to LHS and \frac{1}{5}

5

1

to RHS

= > 4x = \frac{10 - 1}{5}=>4x=

5

10−1

Taking 5 as LCM in RHS

\begin{gathered} = > 4x = \frac{9}{5} \\ \\ = > x = \frac{9}{5} \div 4 \\ \\ = > x = \frac{9}{5} \times \frac{1}{4} \\ \\ \therefore x = \frac{9}{20} \end{gathered}

=>4x=

5

9

=>x=

5

9

÷4

=>x=

5

9

×

4

1

∴x=

20

9