Question

solve this 4 , 5 , 6, question

Answer 1

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Here is your answer
6) P = Rs 2000
A = 2163.20
T = 2 years
n = 2 as Compounded annually
let R = x%
As we know the formula
A = P(1+ R/100)^n
$2163.20 = 2000 \times (1 + \frac{x}{100} ) {}^{2} \\ \frac{2163.20}{2000} = ( \frac{100 + x}{100} ) {}^{2} \\ \frac{432.64}{400} = ( \frac{100 + x}{100} ) {}^{2} \\ ( \frac{20.8}{20} ) {}^{2} = ( \frac{100 + x}{100} ) {}^{2} \\ as \: same \: power \: so \: same \: base \\ \frac{20.8}{20} = \frac{100 + x}{100} \\ 20.8 \times 100 = 20 \times 100 + 20x \\ 20x = 2080 - 2000 \\ x = \frac{80}{20} \\ x = 4\%$
Therefore Rate of interest is 4%

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