Solve this
4x +3y=14 and 3x-4y=23
Answers
Answered by
76
➡HERE IS YOUR ANSWER⬇
Given equations are :
4x + 3y = 14 .....(i)
3x - 4y = 23 .....(ii)
Now,
4x + 3y = 14 .....(i) × 3
3x - 4y = 23 .....(ii) × 4
=>>
12x + 9y = 42
12x - 16y = 92
On subtraction, we get :
25y = - 50
or, y = -2
So y = -2
From (i), putting y = -2, we get :
4x + 3(-2) = 14
=> 4x - 6 = 14
=> 4x = 20
=> x = 5
So x = 5.
Therefore, the required solution is
x = 5 and y = -2.
⬆HOPE THIS HELPS YOU⬅
Given equations are :
4x + 3y = 14 .....(i)
3x - 4y = 23 .....(ii)
Now,
4x + 3y = 14 .....(i) × 3
3x - 4y = 23 .....(ii) × 4
=>>
12x + 9y = 42
12x - 16y = 92
On subtraction, we get :
25y = - 50
or, y = -2
So y = -2
From (i), putting y = -2, we get :
4x + 3(-2) = 14
=> 4x - 6 = 14
=> 4x = 20
=> x = 5
So x = 5.
Therefore, the required solution is
x = 5 and y = -2.
⬆HOPE THIS HELPS YOU⬅
Answered by
21
Hey dear
Hope it helps you.....
Hope it helps you.....
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Sorry but it is wrong
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